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"Natively running the Wolfram Language, the Wolfram Cloud in effect makes every aspect of cloud operations programmable—introducing an unprecedented level of integration, flexibility, simplicity and power into a new generation of cloud technology." ...
Help: ref/ClipPlanesStyle works by planes, graphics 3D has other tricks too (include ones that operate on invisible object having textures on their surface) Help ref/RegionFunction applies to plotting and exclusions the best way to do what...
eqs=2*y*Sinh[m] == c*m*(x*Sinh[m3] + y*Cosh[m3]); Solve[eqs,x] (* appears to solve quickly for x or y not both *) x==Csch[m3] (c m y Cosh[m3] - 2 y Sinh[m])/(c m) but with m1+n2 it does not solve for me and i have no time tonight...
I see mm Help has several white noise examples - perhaps try a different example to see "raw white noise" then simply add that to your (input or output) is one way. as to your definition it is loose but it sounds like your speaking of a general...
i cannot comment on "sigma" seismic-to-noise ratio variance without seeing the material your reading. there would be endless reasonings from which to make such a thing.
Grid is a text formatting function. It would be better if you "do your math" first then provide the result as as input to Grid (rather than attempting math inside Grid[do my math]). You'll find many Mathematica functions may not do math the same...
I'm aware I could access DSolves open source code (3 libraries) found in Help advanced tutorial and know this "to a t". I'm really asking for off the cuff ***quick tips*** by experienced users.
u[x, t] := f[x] h[t]; DSolve[{a D[u[x, t], x] + b D[u[x, t], t] == 0}, u[x, t], {x, t}] ... DSolve: f[x] h[t] cannot be used as a function DSolveValue: "The function h[t] does not have the same number of arguments as...
i can't analyze your work at the moment i'm in a hurry. is y y or is y lamda near that 2Pi? i'm unsure what (^+x) is (handwriting wise). you didn't write "Lim" anywhere. you didn't specify the initial problem or if the solution would move toward...
I think you've been mislead visually. 2 Sin[(2 Pi/4) t +0] + (10/((2 Pi/4)^2 - ((-.0001 + 2 Pi/4)^2))) Sin[(2 Pi/4) t + 0] 2 Sin[(2 Pi/4) t + 0] - (10/(2 Pi/4)) t Cos[(2 Pi/4) t + 0] try plotting those two, (A==2, w0==2Pi/4, w1 very...