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| This factorizes it, in a way: In[13]:= E^(a + b) // ExpToTrig // TrigExpand // Factor Out[13]= (Cosh[a] + Sinh[a]) (Cosh[b] + Sinh[b]) |
| Reading your first block of code, it seems that the functions `LengthS1` and `LengthS2` are exactly the same function, with just different names for the variables. |
| It may help to ask for the `InputForm` of a strange symbol to discover a way to type it: Quantity["ElementaryCharge"] % // InputForm |
| You don't define `P1`. |
| One more workaround: y = ArraySymbol["y", {2}]; NDSolve[{y'[t] == -{1, 0} y[t], y[0] == {1, 2}}, y, {t, 0, 1}] |
| You probably expect `SetPrecision` to behave like `ResourceFunction["DecimalRound"]`. They behave differently. |
| It does not mean that real analytical solutions do not exist. The problem is that their domain is probably very very complicated, as you have a lot of parameters. |
| According to the documentation, `Evaluate` does not take options. Try Assuming[t |
| This version does not give error messages: c[r_] := Minimize[{1 - Abs[1 - F[r]/G[v]], 1 |
| Is the `ColumnKeys[itersela][[i]]` a string? To obtain the symbol `#colKey` you may try `StringJoin`: ColumnKeys[itersela][[i]] -> Function[Total[ToExpression[StringJoin[{"#", ColumnKeys[itersela][[i]]}]]]] |