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Hi, Given this data: good = {{{"foo"}, {0, 1, 0, 0}}}; bad1 = {{{"foo"}, {0, 0, 0, 0}}}; bad2 = {{{"foo"}, {0, "foo", 0, 0}}};I want the test to evaluate to True if the numeric list contains only numbers, but not all zeros. This gets...
Given that: In[201]:= DateDifference[{2011, 1, 19}, {2011, 1, 18}] Out[201]= -1any alternate/creative methods to do the same thing faster? [mcode]In[195]:= Timing[Do[DateDifference[{2011, 1, 19}, {2011, 1, 18}], {1000}];] Out[195]=...