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| Maybe this? Eigenvalues[{{6/10, a}, {2/3, 0}}] Solve[%[[2]] == 1] You can make an interactive simulation: Manipulate[ DiscretePlot[ MatrixPower[{{6/10, a}, {2/3, 0}}, n] . {110, 30}, {n, 0, 10}, Joined ->... |
| Next, I notice you wrote the expression `Point[{0,9/8}]`. There are a couple of things to note here. First, `Point` is used for graphics. The cartesian point as data would be represented as just `{0,9/8}`. Also, just evaluating that expression... |