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If we have two lines in 3-D space, z = a*x + c z = b*y + dHow do I find the plane that passes through those lines?
I have found the solution in case you are curious: I write the plane equation as two line equations:z = a*x + c z = b*y + cfirst, I generate c. Then, I generate a and b. When generating x and y coordinates, I use the following...
Assume that we have three points (a, b, c) in a 3-D space. Those three points determine a plane. How do I calculate the distance from a point d to those point, given only the distances between four points?
Given an equation where a, b, c and d are known, a*x + b*y + c*z = dplease suggest and algorithm to generate random three integers x, y and z those fit into the given equation. Brute force (generating random integers until the equation...