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| I've solved the problem following your instructions. Thank you for your help. |
| Why does the coordinate value containing fractions in this code show a formatting error when display This method is great, and it's more concise. Thank you for your help! |
| -8 x^2 + x^4 + 8 y^2 + 2 x^2 y^2 + y^4 == (x^2 + y^2)^2 - 8 (x^2 - y^2) How to complete the square simultaneously in x and y for the left-hand expression to get the right-hand form? |
| I want the code to implement the following functionality: When a function and its domain interval are supplied, it should generate a table with Row 1: the name of the function Row 2: the interval subdivisions (rendering −∞ and +∞ with the... |
| Plot[x^2, {x, -3, 3}, AxesLabel -> {"x", "y"}, AxesStyle -> Arrowheads@0.035] ![enter image description here][1] Using the code above, the labels of the Cartesian coordinate system are positioned such that the x-axis label 'x' is... |
| ![enter image description here][1] ContourPlot[ Evaluate@(x - 2) Sqrt[x^2 + y^2 - 5] == 0, {x, -3, 3}, {y, -3, 3}, Frame -> False, Axes -> True, AspectRatio -> Automatic] ![enter image description here][2] [1]:... |
| FunctionRange[{y^2/4 + Sqrt[(x - y^2/4)^2 + (E^x - y)^2] + 1}, {x, y}, t] // Quiet Run the code above to get this range: t >= 1.41421 Running the code below does not yield any results. Minimize[{y^2/4 + Sqrt[(x -... |
| The equations of the line and the curve are as follows: line = 2 x - 1 eq = Sin[x + 2 y] == 2 x - y; I solved the problem using the following Mathematica code—does anyone have a better (or simply different) approach? F[x_, y_]... |
| (4 (12 - 8 m + 5 m^2))/(16 - 8 m + 5 m^2) It doesn't work on this. |
| The question is: ![enter image description here][1] vertices = {{0, 0, Sqrt[2/3] - 1/(2 Sqrt[6])}, {0, Sqrt[3]/3, -1/(2 Sqrt[6])}, {-1/2, -Sqrt[3]/ 6, -1/(2 Sqrt[6])}, {1/2, -Sqrt[3]/6, -1/(2 Sqrt[6])} }; ... |