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Obviously the new triangles are not complanar with the plane of the very first triangle. Therefore you look *through*. If you could convince yourself to ease things as much as possible you would - first transform your very first triangle into a...
They are quite visible on the tool bar behind a button `Palettes` like that ![Palettes][1] [1]: http://community.wolfram.com//c/portal/getImageAttachment?filename=palette.PNG&userId=28832
Yes, but, with Clear[f1, f11, fL] f1[x_] := -(ArcTan[(1 + 2 x)/Sqrt[3]]/Sqrt[3]) - 1/3 Log[-1 + x] + 1/6 Log[1 + x + x^2] f11[x_] := -(ArcTan[(1 + 2 x)/Sqrt[3]]/Sqrt[3]) - 1/3 Log[1 - x] + 1/6 Log[1 + x + x^2] fL[x_] :=...
What about taking a limit? In[9]:= FullSimplify[(x^p + 2^p)^(1/p), p 0] Out[10]= 0
Have a look into [Tensor on a vector space][1], especially at the end $T^{0,q}(f)=T^{q,0}(f^{*})^{-1}$. To take $A^{ijkl}B_{klmn} = \delta^{i}_m \delta^{j}_{n}$ serious you could check out [Tensors][2] and [Tensors Tutorial][3] as well as...
> we probably need some statistics beyond the usual anecdotes. The [TIOBE Index for May 2016][1] sees $Mathematica$ on a place 50+. It is a programming community index. If we concede that Nobel Laureats as well as Fields Medallists ... and Mr...
You cannot fix it (recompilation) without being the owner or maintainer of the source code. In Mathematica 10.4.1.0 (Win 10 Prof 64 Bit) it works In[1]:= {{0, 0}, {0.5, 0}, {1, 0}, {1, 1}, {0, 1}}, "BoundaryElements" ->...
In[2]:= DSolve[{y'[x] == x*Log[x], y[1] == 1}, y[x], x] Out[2]= {{y[x] -> 1/4 (5 - x^2 + 2 x^2 Log[x])}} In[3]:= Dimensions[%] Out[3]= {1, 1} and that works In[5]:= Clear[a] a = DSolve[{y'[x] == x*Log[x], y[1] ==...
It looks like a vector plot here (Mathematica 10.4.1.0 Windows 10 Prof 2^6 Bit) Show[{VectorPlot[Normalize[{y, -8 y - 7 x}], {x, -3, 3}, {y, -3, 3}, VectorPoints -> 14, VectorStyle -> Arrowheads[0.015], VectorScale ->...
I need to know how to find the centroid and moment of inertia of such solid. It tends to become numerical, so have a look at [MeshCellCentroid][1], [LaminaData][2], [RegionCentroid][3], [MomentOfInertia][4], [RegionMoment][5] and come up with...