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| How to crunch numbers in Mathematica. How to properly use it to test if a given method solves faster > If I programmed the math algorithm in Mathematica will it be as > efficient as a Xeon processor crunching numbers? ------------------------------------------------------------------------ Mathematica has a Benchmark command. You can run it on... |
| y = (((pnp^2/ x ) + x^2) / pnp) pnp = x * y (((((pnp^2 / x) + x^2)) / x) / pnp) where y = 0 If all of these are true in the factors we wish to find, x and y, is there a limit; a range; that could be computed that said if x is this big then... |
| Are these numbers close that took less than 2 seconds close to the factors? &[Wolfram Notebook][1] [1]: https://www.wolframcloud.com/obj/ef5ae021-fac6-4b21-9fa1-f17736c70407 |
| Clear[x,p]; p=2564855351; x=3; Monitor[While[x |
| Please post code, not images. The plot is accurate, the expression value is highly oscillatory and negative in the plotted domain. ClearAll[eq1, x]; eq1 = -2564855351 + 2564855351 Sqrt[2564855351] x Sqrt[1/(x + 2564855351 x^2)] ... |
| Attached is a PDF that proves this work. I hope it is clear enough. I need feedback because I am trying to write an article. I know it has to be simplified but does anyone follow this? |
| I have used smaller numbers and the graph appeared to work. I post the test here below. I have to use float point. I don’t know the max value an Mathematica type integer can hold. But pnp is an integer, but what I am comparing it too is not. It... |
| We are group of mathematicians. Although I am only an amateur, does no one see that this is a polynomial representation of factoring? This is factoring semi-prime numbers. And an error of 0.17 is the difference of finding an 11 digit semi Prime n... |
| Sorry my browser wasn't working with the reply menu. I didn't have trouble else where. But here is a link to a PDF that explains everything. [Click Here][1] [1]: http://www.constructorscorner.net/Files/20140519TrigPrimes005sec.pdf |
| I really didnt explain this as clearly as needed because I see that no one commented. I will explain again to get some feedback. The picture I posted above is an orthogonal view of the snowflake. We learn in art classes that every object is a... |