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| Discussions |
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| Thank you for the response! since I know K as well where K is: Ax^(1 - a) + Bx^a =K tAy^(1 - a) +B*y^a =K would I get some better way of expressing x in terms of y if I solve it as a system? |
User Portlet | Discussions |
|---|
| Thank you for the response! since I know K as well where K is: Ax^(1 - a) + Bx^a =K tAy^(1 - a) +B*y^a =K would I get some better way of expressing x in terms of y if I solve it as a system? |