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| I am trying to get more significant digists (up to 8 or 10) for the following expression and for the value of $b$ where it is minimum, NMinimize[{(-((4*$\alpha$*b$^3$)/(2 b+$\mu$)^$2$)+(64 b$^5$ (6 b + 4 b$^3$ - 16 b$^5$+ (3 Sqrt[1/$b^2$] b... |
| What's the issue with Fourier Transforms in Mathematica? Why does it always have this DiracDelta? In[1]:= {-1, 1}] Out[4]= b^(3/4) E^-br^2 (2/\[Pi])^(3/4) DiracDelta[k] |
| Integrate$[\frac{q_1}{(q_1^2 + b^2)} Log [(p + q_1^2)+m^2]$,${q_1,0,Infinity}]$ gives a different answer than Integrate$[\frac{a}{(a^2 + b^2)} Log [(p + a^2)+m^2]$,${a,0,Infinity}]$ Using Mathematica 10.0 Why? |
| Hello, Could someone point me to approaches at solving the following type of integral equation in Mathematica (p and q are variables, " f " is a function of either p, or q , and \omega is a function of p, q or both p and q, as well as \mu and m. A,... |
| For an expression like E^(I x Subscript[p1, m] - I x Subscript[p1, \[Mu]] - I x Subscript[p2, m] - I x Subscript[p2, \[Mu]]) how does one go about substituing `E^(x*Subscript[p1, m])` with `E^(Subscript[\[Omega], Subscript[p1, m]] t... |
| Assuming[{p, m, \[CapitalLambda], k} \[Element] Reals, Integrate[k/(2 (k^2 + m^2) (-k + p)), {p, 0, \[CapitalLambda]}]] Mathematica's answer is ConditionalExpression[(k Log[1 - \[CapitalLambda]/k])/(2 (k^2 + m^2)), \[CapitalLambda] == 0 ||... |
| Trying this plot command Plot[p^2/((p^2 - k^2) (p^2 + m^2)), {p, 0, k}] and Mathematica gives some cryptic message! |
| I am trying the following two integrals (college computer, with Mathematica 9) Integrate[(p^2)/(p^2 - Subscript[E, 1] m), {p, 0, \[CapitalLambda]}] and Integrate[(p^2)/((p^2 - Subscript[E, 1] m) (p^2 + m^2)), {p, 0, \[CapitalLambda]}] I... |
| Appreciate tips on how write a Mathematica script that would 1. Wait for user input, that contains a long string which includes blank spaces, i.e. no commas etc. 2. Do an integral over a predefined variable using input from Step 1. 3. Use... |
| The following integration returns back the input, but the integral can actually be evaluated by hand. What is wrong with this -- is it Mathematica 9 that does this? [mcode]Integrate[DiracDelta[-k1-q1] DiracDelta[k1-pm] DiracDelta[pm-(-q1)]... |