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[✓] Use the DSolve y[x] as a function?

GROUPS:

I am doing a lab for class, but I am stuck on this issue. I do not understand what the problem is even after looking into it. Does anyone else see the problem? Thanks!

POSTED BY: Paul Price
Answer
3 months ago
In[1]:= DSolve[t^3 y'[t] + 4 y[t]^2 == 0, y[t], t]

Out[1]= {{y[t] -> -(t^2/(2 + t^2 C[1]))}}
POSTED BY: Frank Kampas
Answer
3 months ago

Group Abstract Group Abstract