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Good approach. Thank you.
If you have a difference equation like this: eqn = y[n + 2] - 5 y[n + 1] + 6 y[n] == 3 (0.5)^(1 + n) UnitStep[1 + n] + 5 (0.5)^n UnitStep[n] 6 y[n] - 5 y[1 + n] + y[2 + n] == 5 0.5^n UnitStep[n] + 3 0.5^(1 +...