0
|
12989 Views
|
2 Replies
|
0 Total Likes
View groups...
Share
GROUPS:

# How to find Laplace Transform

Posted 11 years ago
 How to find Laplace Transform of the following function with respect to x :Product[2 - (Gamma[Subscript[m, i], Subscript[m, i]/Subscript[\[CapitalOmega], i] (x/\[Gamma])^(1/ Subscript[n, i])]/Gamma[Subscript[m, i]] + Gamma[Subscript[t, i], Subscript[t, i]/Subscript[\[Rho], i] (x/\[Gamma])^(1/Subscript[k, i])]/ Gamma[Subscript[t, i]]), {i, 1, M}]Thanks for your support!
2 Replies
Sort By:
Posted 11 years ago
 I'm an amateur to Laplace transforms, but it looks to me that you can express your eventual solution in terms of integrals of typeLaplaceTransform[Gamma[m, C x^(1/n)], x, z]with various m, C, and n.Assuming that your n's are positive integers and looking at the first few such results, it looks to me as if there is pattern lurking, which I leave to you to determine:  In[1]:= Table[   n -> LaplaceTransform[Gamma[m, C x^(1/n)], x, z], {n, 1, 6}]    Out[1]= {1 -> ((1 - ((C + z)/C)^-m) Gamma[m])/z,   2 -> 1/2 z^(     1/2 (-3 - m)) (2 z^((1 + m)/2) Gamma[m] +       C^m (-Sqrt[z] Gamma[m/2] Hypergeometric1F1[m/2, 1/2, C^2/(4 z)] +           C Gamma[(1 + m)/2] Hypergeometric1F1[(1 + m)/2, 3/2, C^2/(            4 z)])), 3 -> 1/6 z^(   1/3 (-5 - m)) (6 z^((2 + m)/3) Gamma[m] +     2 C^(1 + m) z^(1/3)       Gamma[(1 + m)/       3] HypergeometricPFQ[{1/3 + m/3}, {2/3, 4/3}, -(C^3/(27 z))] -     C^(2 + m)       Gamma[(2 + m)/       3] HypergeometricPFQ[{2/3 + m/3}, {4/3, 5/3}, -(C^3/(27 z))] -     2 C^m z^(2/3)       Gamma[m/       3] HypergeometricPFQ[{m/3}, {1/3, 2/3}, -(C^3/(27 z))]), 4 -> 1/24 z^(   1/4 (-7 - m)) (24 z^((3 + m)/4) Gamma[m] +     6 C^(1 + m) Sqrt[z]       Gamma[(1 + m)/       4] HypergeometricPFQ[{1/4 + m/4}, {1/2, 3/4, 5/4}, C^4/(       256 z)] -     3 C^(2 + m) z^(1/4)       Gamma[(2 + m)/       4] HypergeometricPFQ[{1/2 + m/4}, {3/4, 5/4, 3/2}, C^4/(       256 z)] +     C^(3 + m)       Gamma[(3 + m)/       4] HypergeometricPFQ[{3/4 + m/4}, {5/4, 3/2, 7/4}, C^4/(       256 z)] -     6 C^m z^(3/4)       Gamma[m/4] HypergeometricPFQ[{m/4}, {1/4, 1/2, 3/4}, C^4/(       256 z)]), 5 -> 1/120 z^(   1/5 (-9 - m)) (120 z^((4 + m)/5) Gamma[m] +     24 C^(1 + m) z^(3/5)       Gamma[(1 + m)/       5] HypergeometricPFQ[{1/5 + m/5}, {2/5, 3/5, 4/5, 6/5}, -(C^5/(        3125 z))] -     12 C^(2 + m) z^(2/5)       Gamma[(2 + m)/       5] HypergeometricPFQ[{2/5 + m/5}, {3/5, 4/5, 6/5, 7/5}, -(C^5/(        3125 z))] +     4 C^(3 + m) z^(1/5)       Gamma[(3 + m)/       5] HypergeometricPFQ[{3/5 + m/5}, {4/5, 6/5, 7/5, 8/5}, -(C^5/(        3125 z))] -     C^(4 + m)       Gamma[(4 + m)/       5] HypergeometricPFQ[{4/5 + m/5}, {6/5, 7/5, 8/5, 9/5}, -(C^5/(        3125 z))] -     24 C^m z^(4/5)       Gamma[m/       5] HypergeometricPFQ[{m/5}, {1/5, 2/5, 3/5, 4/5}, -(C^5/(        3125 z))]), 6 -> 1/720 z^(   1/6 (-11 - m)) (720 z^((5 + m)/6) Gamma[m] +     120 C^(1 + m) z^(2/3)       Gamma[(1 + m)/       6] HypergeometricPFQ[{1/6 + m/6}, {1/3, 1/2, 2/3, 5/6, 7/6},       C^6/(46656 z)] -     60 C^(2 + m) Sqrt[z]       Gamma[(2 + m)/       6] HypergeometricPFQ[{1/3 + m/6}, {1/2, 2/3, 5/6, 7/6, 4/3},       C^6/(46656 z)] +     20 C^(3 + m) z^(1/3)       Gamma[(3 + m)/       6] HypergeometricPFQ[{1/2 + m/6}, {2/3, 5/6, 7/6, 4/3, 3/2},       C^6/(46656 z)] -     5 C^(4 + m) z^(1/6)       Gamma[(4 + m)/       6] HypergeometricPFQ[{2/3 + m/6}, {5/6, 7/6, 4/3, 3/2, 5/3},       C^6/(46656 z)] +     C^(5 + m)       Gamma[(5 + m)/       6] HypergeometricPFQ[{5/6 + m/6}, {7/6, 4/3, 3/2, 5/3, 11/6},       C^6/(46656 z)] -     120 C^m z^(5/6)       Gamma[m/6] HypergeometricPFQ[{m/6}, {1/6, 1/3, 1/2, 2/3, 5/6},       C^6/(46656 z)])}
Posted 11 years ago
 Dear Peter,Thanks for your answer. In fact,  I would like to know which theorem you used to build your formula as I could not see Product function for i (1 to M) which has direct efferct on the output..Your cooperation is highly appreciated!!
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.