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Mathematics Equation Solving Wolfram Language Numerical Computation

Posted 9 years ago

POSTED BY: Romildo Junior

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Posted 9 years ago

Thanks Hans, that gave me a very high value like -3521, I think that might not be the answer. I have a fortran code that uses the singularity subtraction to calculate and it gives a value of like 0.1000 for the integral from -1 to 1, I wanted to know if Mathematica could solve a Integral like that without a external code or technique. I am starting to think that Mathematica maybe cannot solve this integral. I wanted to upgrade my code to Mathematica by using its functions to solve the integral more easily. If anyone got a way to go please help

POSTED BY: Romildo Junior

Posted 9 years ago

You say the singularity must lie within the interval. A perhaps stupid question: what about calculating the integral from -1+x to 1 for several small x-es and then fitting a curve through the { 1 - x , intergralvalue} points , for example a polynomial (perhaps of second order ) . Then let x = 0 in this function?

POSTED BY: Hans Dolhaine

Posted 9 years ago

Thanks for the reply, It is a strong singularity of type (1/r) , no adaptivity technique seems to be working, and cauchy could only be evaluated if the singular point is in the interval . I tried to solve it analytically like and got the input back! This integral is getting on my nerves !