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[?] Substitute a - z == y into an equation?

Posted 4 years ago
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Hello, I was wondering with the following equation:

a^4 - 4 a^3 z + 6 a^2 z^2 - 4 a z^3 + z^4

how can I substitute:

a - z == y

to get:

y^4

Thanks

3 Replies
a^4 - 4 a^3 z + 6 a^2 z^2 - 4 a z^3 + z^4
% /. a -> y + z // Simplify
Posted 4 years ago

very nice, works like a charm...thanks for the reply!

Posted 4 years ago

Sometimes giving Simplify the optional second argument, which are the assumptions that you are telling Simplify that it can depend on always being true and which it is free to make use of as it sees fit, can accomplish interesting and helpful things.

Simplify[a^4 - 4 a^3 z + 6 a^2 z^2 - 4 a z^3 + z^4, a - z == y]

immediately returns

y^4
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