# Solve the brick problem/perfect box problem?

Posted 3 years ago
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 eg can u use time as a scale? for measuring the size? An Euler brick is a cuboid that possesses integer edges a>b>c and face diagonalsA= 9B= 6C= 2Dab = (9^2 + 6^2) ^(1/2) = 10.8166....Dbc = (6^2 + 2^2) ^(1/2) = 6.32455....Dac= ( 9^2 + 2^2 ) ^(1/2) = 9.21954....Dabc= (2^2 + 6^2 + 9^2 ) ^(1/2) = 11A= (9ms)B= (6ms)C= (2ms) Dab= ((9ms)^2 + (6ms)^2 ) ^(1/2) = 10.82msDbc= ((6ms)^2 + (2ms)^2 ) ^(1/2) = 6.325ms Dac= ((9ms)^2 + (2ms)^2 ) ^(1/2) = 9.22msDabc = ((9ms)^2 + (6ms)^2 + (2ms)^2 ) ^(1/2) = 11msA= 240B= 117C= 44dab = (240^2 + 117^2) ^(1/2) = 267dab = ((240ms)^2 + (117ms)^2) ^(1/2) = 267msdac = (240^2 + 44^2) ^(1/2) = 244dac = ((240ms)^2 + (44ms)^2) ^(1/2) = 244msdbc = (117^2 + 44^2) ^(1/2) = 125dbc = ((117ms)^2 + (44ms)^2) ^(1/2) = 125msdabc =(240^2 + 117^2 + 44^2 ) ^(1/2) = 270.601182....dabc =((240ms)^2 + (117ms)^2 + (44ms)^2 ) ^(1/2) = 270.6mscan you do it this way?a = 1 or (1ms)(1^2 + 1^2 ) ^(1/2) = 1.41421......((1ms)^2 + (1ms)^2 ) ^(1/2) = 1.414 ms (1^2 + 1^2 +1^2 ) ^(1/2) = 1.73205......((1ms)^2 + (1ms)^2 + (1ms)^2) ^(1/2) = 1.732 ms (milliseconds)eg can u use time as a scale? for measuring the size? Answer
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Posted 3 years ago
 Hi AaronHave you read this, it should point you in the right direction or give you an idea which way to go next.https://en.wikipedia.org/wiki/Euler_brick Answer
Posted 3 months ago
 An Euler brick is a cuboid that possesses integer edges a>b>c and face diagonals A= 9 B= 6 C= 2 Dab = (9^2 + 6^2) ^(1/2) = 10.8166.... Dbc = (6^2 + 2^2) ^(1/2) = 6.32455.... Dac= ( 9^2 + 2^2 ) ^(1/2) = 9.21954.... Dabc= (2^2 + 6^2 + 9^2 ) ^(1/2) = 11 A= (9ms) B= (6ms) C= (2ms) Dab= ((9ms)^2 + (6ms)^2 ) ^(1/2) = 10.82ms Dbc= ((6ms)^2 + (2ms)^2 ) ^(1/2) = 6.325ms Dac= ((9ms)^2 + (2ms)^2 ) ^(1/2) = 9.22ms Dabc = ((9ms)^2 + (6ms)^2 + (2ms)^2 ) ^(1/2) = 11ms A= 240 B= 117 C= 44 dab = (240^2 + 117^2) ^(1/2) = 267 dab = ((240ms)^2 + (117ms)^2) ^(1/2) = 267ms dac = (240^2 + 44^2) ^(1/2) = 244 dac = ((240ms)^2 + (44ms)^2) ^(1/2) = 244ms dbc = (117^2 + 44^2) ^(1/2) = 125 dbc = ((117ms)^2 + (44ms)^2) ^(1/2) = 125ms dabc =(240^2 + 117^2 + 44^2 ) ^(1/2) = 270.601182.... dabc =((240ms)^2 + (117ms)^2 + (44ms)^2 ) ^(1/2) = 270.6ms can you do it this way?a = 1 or (1ms)(1^2 + 1^2 ) ^(1/2) = 1.41421......((1ms)^2 + (1ms)^2 ) ^(1/2) = 1.414 ms(1^2 + 1^2 +1^2 ) ^(1/2) = 1.73205......((1ms)^2 + (1ms)^2 + (1ms)^2) ^(1/2) = 1.732 ms (milliseconds) Answer