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Solve the brick problem/perfect box problem?

Posted 3 years ago
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eg can u use time as a scale? for measuring the size? An Euler brick is a cuboid that possesses integer edges a>b>c and face diagonals

A= 9

B= 6

C= 2

Dab = (9^2 + 6^2) ^(1/2) = 10.8166....

Dbc = (6^2 + 2^2) ^(1/2) = 6.32455....

Dac= ( 9^2 + 2^2 ) ^(1/2) = 9.21954....

Dabc= (2^2 + 6^2 + 9^2 ) ^(1/2) = 11

A= (9ms)

B= (6ms)

C= (2ms)

Dab= ((9ms)^2 + (6ms)^2 ) ^(1/2) = 10.82ms

Dbc= ((6ms)^2 + (2ms)^2 ) ^(1/2) = 6.325ms

Dac= ((9ms)^2 + (2ms)^2 ) ^(1/2) = 9.22ms

Dabc = ((9ms)^2 + (6ms)^2 + (2ms)^2 ) ^(1/2) = 11ms

A= 240

B= 117

C= 44

dab = (240^2 + 117^2) ^(1/2) = 267

dab = ((240ms)^2 + (117ms)^2) ^(1/2) = 267ms

dac = (240^2 + 44^2) ^(1/2) = 244

dac = ((240ms)^2 + (44ms)^2) ^(1/2) = 244ms

dbc = (117^2 + 44^2) ^(1/2) = 125

dbc = ((117ms)^2 + (44ms)^2) ^(1/2) = 125ms

dabc =(240^2 + 117^2 + 44^2 ) ^(1/2) = 270.601182....

dabc =((240ms)^2 + (117ms)^2 + (44ms)^2 ) ^(1/2) = 270.6ms

can you do it this way?

a = 1 or (1ms)

(1^2 + 1^2 ) ^(1/2) = 1.41421......

((1ms)^2 + (1ms)^2 ) ^(1/2) = 1.414 ms

(1^2 + 1^2 +1^2 ) ^(1/2) = 1.73205......

((1ms)^2 + (1ms)^2 + (1ms)^2) ^(1/2) = 1.732 ms (milliseconds)

eg can u use time as a scale? for measuring the size?

2 Replies
Posted 3 years ago

Hi Aaron

Have you read this, it should point you in the right direction or give you an idea which way to go next.

https://en.wikipedia.org/wiki/Euler_brick

Posted 25 days ago

An Euler brick is a cuboid that possesses integer edges a>b>c and face diagonals

A= 9

B= 6

C= 2

Dab = (9^2 + 6^2) ^(1/2) = 10.8166....

Dbc = (6^2 + 2^2) ^(1/2) = 6.32455....

Dac= ( 9^2 + 2^2 ) ^(1/2) = 9.21954....

Dabc= (2^2 + 6^2 + 9^2 ) ^(1/2) = 11

A= (9ms)

B= (6ms)

C= (2ms)

Dab= ((9ms)^2 + (6ms)^2 ) ^(1/2) = 10.82ms

Dbc= ((6ms)^2 + (2ms)^2 ) ^(1/2) = 6.325ms

Dac= ((9ms)^2 + (2ms)^2 ) ^(1/2) = 9.22ms

Dabc = ((9ms)^2 + (6ms)^2 + (2ms)^2 ) ^(1/2) = 11ms

A= 240

B= 117

C= 44

dab = (240^2 + 117^2) ^(1/2) = 267

dab = ((240ms)^2 + (117ms)^2) ^(1/2) = 267ms

dac = (240^2 + 44^2) ^(1/2) = 244

dac = ((240ms)^2 + (44ms)^2) ^(1/2) = 244ms

dbc = (117^2 + 44^2) ^(1/2) = 125

dbc = ((117ms)^2 + (44ms)^2) ^(1/2) = 125ms

dabc =(240^2 + 117^2 + 44^2 ) ^(1/2) = 270.601182....

dabc =((240ms)^2 + (117ms)^2 + (44ms)^2 ) ^(1/2) = 270.6ms

can you do it this way?

a = 1 or (1ms)

(1^2 + 1^2 ) ^(1/2) = 1.41421......

((1ms)^2 + (1ms)^2 ) ^(1/2) = 1.414 ms

(1^2 + 1^2 +1^2 ) ^(1/2) = 1.73205......

((1ms)^2 + (1ms)^2 + (1ms)^2) ^(1/2) = 1.732 ms (milliseconds)

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