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Mathematica

Wrong result for very simple series with Floor

Mario Weitzer
Posted 11 years ago
On Mathematica 8 the following sum
Sum[Floor[2/2^p], {p, 1, Infinity}]
evaluates to 0, which is obviously wrong.
Sum[Floor[2/2^p], {p, 1, 10}]
evaluates correctly to 1.
POSTED BY: Mario Weitzer
2 Replies
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Thank you for pointing this out.

Reports of incorrect behavior are best handled by sending the
information to support@wolfram.com or using the feedback form at
http://www.wolfram.com/support/contact/email/.

This has been passed on to the Technical Support group for
processing.
POSTED BY: Bruce Miller
Jari Kirma
Jari Kirma
Posted 11 years ago
Seems like a bug to me.
Sum[Floor[2^-p], {p, 0, Infinity}]

(* 0 *)

Sum[Floor[2^-p], {p, #, Infinity}] & /@ {-1, 0, 1}

(* {3, 0, 0} *)

Strangely enough, this works:
Sum[Floor[2^-p], {p, {-1, 0, 1}, Infinity}]

(* {3, 1, 0} *)
POSTED BY: Jari Kirma
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