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integral of (Sin(x)/x)^2

Posted 10 years ago
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What is the most easiest way to solve the integral (sin(x)/x)^2 with limits from -infinity to infinity.

(sin(x)/x)^2 is the "squared Sinc(x)" function
POSTED BY: Rahul Pokhriyal
Posted 10 years ago
Pedantically speaking, you want the following (note that Sin/x really has a discontinuity at x=0, but Sinc doesn't):
Integrate[Sinc[x]^2, {x, -Infinity, Infinity}]
(* Pi *)
This also works, but technically it's not the same:
Integrate[(Sin[x]/x)^2, {x, -Infinity, Infinity}]
(* Pi *)
POSTED BY: Jari Kirma
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