# "Loosely Approximating" a continuous curve

Posted 2 months ago
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 I'm trying to save some CPU cycles in an application by finding a curve formula that's "very similar but simpler" than the ones I have. I'm wondering what the best way to do this in Wolfram Alpha is. I tried to split it up into a table and then run cubic fit on it but Alpha wasn't really having that. Any suggestions?Here are the two formulas I'm attempting to approximate: plot 10^((( (x*1.4+.3)^(.3) )*128-128)/20) from x=0 to 1 plot 10^((( (1-(x-.5))^.3 )*128-128)/20) from x=0 to 1 Here they are as tables: Table[ 10^((( (x*1.4+.3)^(.3) )*128-128)/20) ,{x,0,1,.05}] Table[ 10^((( (1-(x-.5))^.3 )*128-128)/20) ,{x,0,1,.05}] And here's the syntax I tried. quadratic fit[Table[ 10^((( (1-(x-.5))^.3 )*128-128)/20) ,{x,0,1,.05}]] Here's what it looks like in Apple Grapher:
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Posted 2 months ago
 Please edit to add the actual Mathematica code (not a picture of code) for the function of interest.
Posted 2 months ago
 Dan, Edited original post. Sorry for not being as rigorous as I could have been.
Posted 2 months ago
 Using FindFormula function. See attached files. Attachments:
Posted 2 months ago
 Mariusz, I don't know how you generated that pdf or what a .nb file is but I now feel like I need to read a few books on how to use Wolfram Alpha. Either way, I see generally how you did this and I'm deeply appreciative!