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Solve the following simple system of equations?

Posted 7 years ago

Hi I can't get this simple system to solve. I want to know a, b, and c which are flow rates and I know the mole fractions, but mathematica won't solve for it. Please help.

Solve[yCO == (0.015 a + 0.05 b)/(a + b + c) && 
  yCO2 == (0.07*a)/(a + b + c) && yN2 ==  1 - yCO - yCO2, {a, b, c}]
POSTED BY: Jonathan Witt
2 Replies

Adding option MaxExtraConditions -> All to Solve helps:

Solve[Rationalize[
  yCO == (0.015 a + 0.05 b)/(a + b + c) && 
   yCO2 == (0.07*a)/(a + b + c) && yN2 == 1 - yCO - yCO2, 0], {a, b, 
  c}, MaxExtraConditions -> All]

 (* {{a -> ConditionalExpression[0, 
     yCO2 == 0 && yCO == 0 && yN2 == 1 && c != 0], 
   b -> ConditionalExpression[0, 
     yCO2 == 0 && yCO == 0 && yN2 == 1 && c != 0]}, {a -> 
    ConditionalExpression[0, 
     yCO2 == 0 && yCO + yN2 == 1 && yCO != 0 && b != 0], 
   c -> ConditionalExpression[(b - 20 b yCO)/(20 yCO), 
     yCO2 == 0 && yCO + yN2 == 1 && yCO != 0 && b != 0]}, {b -> 
    ConditionalExpression[-((3 a)/10), 
     yCO == 0 && yCO2 + yN2 == 1 && yCO2 != 0 && a != 0], 
   c -> ConditionalExpression[-((7 (-a + 10 a yCO2))/(100 yCO2)), 
     yCO == 0 && yCO2 + yN2 == 1 && yCO2 != 0 && a != 0]}, {b -> 
    ConditionalExpression[(a (14 yCO - 3 yCO2))/(10 yCO2), 
     yCO + yCO2 + yN2 == 1 && yCO2 != 0 && yCO != 0 && a yCO != 0], 
   c -> ConditionalExpression[(
     3 a - 200 a yCO + (a (14 yCO - 3 yCO2))/yCO2 - (
      20 a yCO (14 yCO - 3 yCO2))/yCO2)/(200 yCO), 
     yCO + yCO2 + yN2 == 1 && yCO2 != 0 && yCO != 0 && a yCO != 0]}}*)
POSTED BY: Mariusz Iwaniuk
Posted 7 years ago
POSTED BY: Jim Baldwin
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