Group Abstract

Message Boards

WOLFRAM COMMUNITY

4.4K Views

4 Replies

1 Total Like

View groups...

Follow this post

Share this post:

GROUPS:

Graphics and Visualization Wolfram Language

Plot a ListLinePlot with time stamps?

T P

Posted 7 years ago

I have the following command: ListLinePlot[Transpose[sampleData[[{2, 18}]]], Frame -> True, PlotRange -> {All, {0, 5000}}, FrameLabel -> {"Latitude (\[Degree])", "\!\(\SubscriptBox[\(T\), \(e\)]\) (K)"}] If I want to get the timestamp, which corresponds to sampleData[{1}] for Latitude >40 and Latitude <80, how should the command be rewritten? I tried, ListLinePlot[Transpose[sampleData[[{2, 18}]] /; sampleData[[2]] >= 40 && sampleData[[2]] <= 80], Frame -> True, PlotRange -> {All, {0, 5000}}, FrameLabel -> {"Latitude (\[Degree])", "\!\(\SubscriptBox[\(T\), \(e\)]\) (K)"}] but it doesn't work. Thanks

enter image description here

I have the following command:

ListLinePlot[Transpose[sampleData[[{2, 18}]]], Frame -> True, 
 PlotRange -> {All, {0, 5000}}, 
 FrameLabel -> {"Latitude (\[Degree])", 
   "\!\(\*SubscriptBox[\(T\), \(e\)]\) (K)"}]

If I want to get the timestamp, which corresponds to sampleData[{1}] for Latitude >40 and Latitude <80, how should the command be rewritten?

I tried,

ListLinePlot[Transpose[sampleData[[{2, 18}]] /; sampleData[[2]] >= 40 && sampleData[[2]] <= 80], Frame -> True, 
PlotRange -> {All, {0, 5000}}, 
FrameLabel -> {"Latitude (\[Degree])", 
"\!\(\*SubscriptBox[\(T\), \(e\)]\) (K)"}]

but it doesn't work.

Thanks

POSTED BY: T P

4 Replies

Sort By:

T P

Posted 7 years ago

Hi Rohit, Transpose[sampleData[[{1, 2, 15}]]] {{2014, 11, 1, 1, 1, 0.696}, 21.1056, 248160.}, {{2014, 11, 1, 1, 1, 1.197}, 21.0738, 249216.},.............................. Index 1 refers to the timestamp which I must retrieve, index 2 is the x-axis variable which I must retrieve from # >= 40 && # <= 80 & I will also need data from Index 15 and 18 How can I retrieve a list of these data points?

POSTED BY: T P

Rohit Namjoshi

Posted 7 years ago

If your data looks like this data = {{{2014, 11, 1, 1, 1, 0.696}, 21.1056, 248160.}, {{2014, 11, 1, 1, 1, 1.197}, 41.0738, 249216.}, {{2014, 11, 1, 1, 1, 2.197}, 60.0738, 249216.}} Then this will give the elements where the second index (x value) is in the desired range Select[data, #[[2]] >= 40 && #[[2]] <= 80 &] (* {{{2014, 11, 1, 1, 1, 1.197}, 41.0738, 249216.}, {{2014, 11, 1, 1, 1, 2.197}, 60.0738, 249216.}} ) To get just the timestamp and x value Most /@ Select[data, #[[2]] >= 40 && #[[2]] <= 80 &] ( {{{2014, 11, 1, 1, 1, 1.197}, 41.0738}, {{2014, 11, 1, 1, 1, 2.197}, 60.0738}} *)

If your data looks like this

data = {{{2014, 11, 1, 1, 1, 0.696}, 21.1056, 248160.}, 
        {{2014, 11, 1, 1, 1, 1.197}, 41.0738, 249216.},
        {{2014, 11, 1, 1, 1, 2.197}, 60.0738, 249216.}}

Then this will give the elements where the second index (x value) is in the desired range

Select[data, #[[2]] >= 40 && #[[2]] <= 80 &]
(* {{{2014, 11, 1, 1, 1, 1.197}, 41.0738, 249216.}, {{2014, 11, 1, 1, 1, 2.197}, 60.0738, 249216.}} *)

To get just the timestamp and x value

Most /@ Select[data, #[[2]] >= 40 && #[[2]] <= 80 &]
(* {{{2014, 11, 1, 1, 1, 1.197}, 41.0738}, {{2014, 11, 1, 1, 1, 2.197}, 60.0738}} *)

POSTED BY: Rohit Namjoshi

T P

Posted 7 years ago

Hi Rohit, this worked.

POSTED BY: T P

Rohit Namjoshi

Posted 7 years ago

POSTED BY: Rohit Namjoshi

Reply to this discussion

Reply Preview

Attachments

Remove Add a file to this post

Follow this discussion

or Discard

Feedback