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Make a matrix from an Array?

????? ?????????
Posted 6 years ago

I have this code:

n=Input[];
Array[mat,{n,n}];
For[i = 1, i < n+1, i++,
    For[j = 1, j < n+1, j++,
       mat[i,j]=0;
    ]
]
d=Det[mat];
Print[d];

And when I input "2", the result is 1, which can't be true. Is there something with an Array being a matrix?
POSTED BY: ????? ?????????
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Bo Brymer
Bo Brymer, Self
Posted 6 years ago 
d_j^n2=Input [{n,d_d} ]; array=[mat,{n,n_d^d}]; For[i = 1, i < n+1, i++,     For[j = 1, j < n+1, j++,        mat[i,j]=0;     ] ] d=Det[mat,{n,n}]; Print[d];
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POSTED BY: Bo Brymer

If I understand what you're trying to accomplish, which is to create a square zero-matrix, then the following does what you want:

      n = Input[];
      mat = ConstantArray[0, {n, n}];
      Det[mat]
(* 0 *)

There's no earthly reason to use a Fortran-like (or Matlab-like) do loop.

Moreover, if you're filling the matrix with 0's, you would surely already know its determinant will be 0,
POSTED BY: Murray Eisenberg

Your mat is the head of the array. The array itself is Array[mat,{n,n}]:

n = Input[];
myArray = Array[mat, {n, n}];
For[i = 1, i < n + 1, i++, 
 For[j = 1, j < n + 1, j++, mat[i, j] = 0;]]
d = Det[myArray]
POSTED BY: Gianluca Gorni
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