When using DSolve or DSolveValue in calculating a solution for y’’ + 5y’ == 0, I am getting the answer of C1 -1/5 e^(-5x) + C2 – see attached. I have solved this equation several different ways using different methods without generating the -1/5 multiplier and cannot understand what is generating the –1/5 multiplier using DSolve and DSolveValue.

In testing, it appears that the solution given by DSolve and DSolveValue is in fact a valid solution but it just seems unnecessary for the additional multiplier.

Most likely the confusion is because of something that I do not understand so I would certainly appreciate some clarification as to why the multiplier is being generated.

Thanks so much,

Mitch Sandlin

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