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Calculate a definite double Integral for a trigonometric function?

Posted 5 years ago

Hello all! I'm having difficulty understanding why the calculator is returning the answer for the question posted within the screenshot.

The Integral in question can be shown to evaluate to 50pi.

Can anyone see what I am doing wrong?

I apologize for all of the trivial questions, but I find Mathematica to be a wonderful tool for checking my work!

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POSTED BY: Luke Paluso
2 Replies

The sine function is Sin, not sin.

POSTED BY: John Doty
Posted 5 years ago

Well met. Have a good night!

POSTED BY: Luke Paluso
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