# Wrong limit?

Posted 2 months ago
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 Hello! I am a student trying to understand why this limit [lim n->+infinity (nsen(n)+n^2)/(n^(1/3)+tan^-1((n^2)/(n+1)))] gives me no result on wolfram while it seems to me that the result is plus infinity. I thought that there is a strange calculation about the function of the tan^-1 which I can't explain. Answer
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Posted 2 months ago
 Probably unable to interpret "nsen(n)". Answer
Posted 2 months ago
 Should "nsen(n) be the product of n and the sine of n? If so -- and using correct Wolfram language syntax:  Limit[(n Sin[n] + n^2)/(n^(1/3) + ArcTan[n^2/(n + 1)]), n -> \[Infinity]] (* \[Infinity] *) Answer
Posted 2 months ago I copied the correction and this is the limit I'm looking for, though I don't know why the result isn't infinity. Answer
Posted 2 months ago
 Version 12.0 of Mathematica seems to be fine with this.Limit[(n*Sin[n] + n^2)/(n^(1/3) + ArcTan[n^2/(n + 1)]), n -> Infinity](* Out= [Infinity] *)Offhand I have no idea why W|A is faltering. Answer