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# How can I make the most abbreviated expression of the resulting matrix?

Posted 11 years ago
 Hi, I am trying to produce the most abbreviated expression of the formulas inside the resulting matrixof the following code:as = Variance[Table[u[i, t] - u[i, t - 1], {t, 1, 3}, {i, 1, 2}]];MatrixForm[Simplify[as, Element[u[_, _], Reals]]];cv = Covariance[Table[u[i, t] - u[i, t - 1], {t, 1, 3}, {i, 1, 2}]];MatrixForm[Simplify[cv, Element[u[_, _], Reals]]];MatrixForm[D[Simplify[((as + 2*cv)^(1/2))*F, Element[u[_, _], Reals]], u[1, 2]]]--> I am trying to abbreviate the result into the most simplfied expression of the resulting matrix only except the diagonal elements.If so, how can I do this work?Besides, when I try the different partial derivative formula like:MatrixForm[D[Simplify[((as + 2*cv)^(1/2))*F, Element[u[_, _], Reals]], u[1, 1]]]The result of the position (1,1) of the resulting matrix is:6^(1/2)* F *Abs'*[u[1, 0] - 2 u[1, 1] + u[1, 2]]How can I fix this " Abs' " into the real number format that I can use practically? I would greatly appreciate if I could get any helps on this problem. Thank you very much!