Thank you!

It seems like the FindSequenceFunctin works with the list of numbers, not with the one type of long variable.;

The type of term that I want to abbreviate is like:

(Sqrt[3] *F* (u[1, 0] - 2 u[1, 1] + u[1, 2] + 2 (u[2, 0] - 2 u[2, 1] + u[2, 2])))/(2 \(u[1, 0]^2 + 3 u[1, 1]^2 + 3 u[1, 2]^2 - 3 u[1, 2] u[1, 3] + u[1, 3]^2 + 2 u[1, 3] u[2, 0] + u[2, 0]^2 - 6 u[1, 2] u[2, 1] - 3 u[2, 0] u[2, 1] + 3 u[2, 1]^2 + 12 u[1, 2] u[2, 2] - 6 u[1, 3] u[2, 2] - 3 u[2, 1] u[2, 2] + 3 u[2, 2]^2 - 3 u[1, 1] (u[1, 2] + 2 (u[2, 0] - 2 u[2, 1] + u[2, 2])) + (-6 u[1, 2] + 4 u[1, 3] + u[2, 0] - 3 u[2, 2]) u[2, 3] + u[2, 3]^2 + u[1, 0] (-3 u[1, 1] + u[1, 3] + 4 u[2, 0] - 6 u[2, 1] + 2 u[2, 3])))


-> which is like a very long one number, not the list of numbers.

If this is so, is there any other function that may work with this sort of problem?

If not, is there any alternative software that can do this sort of work..?


Thank you very very much again!

Thank you!

I am trying to use the result of the following code: --> Here, the variable at the right end of the last line which is "u[1,1]" will vary according to my needs,

such as u[1,2], u[2,2], u[2,3] and so on.

I am trying to find a pattern here and try to find a general expression for the resulting equation.

Is there a way to do so..?

Thank you so much!