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Find the inverse of function h by a numerical way ?

Posted 18 days ago
6 Replies
3 Total Likes

Hello guys, Please I have a question: I need to know the inverse of function "h= a + Q" defined as follows:

(*Définit la fonction indicatrice*)
indicator[x_] := Piecewise[{{1, 0 < x < \[Pi]/2}}, 0];
(*Semi groupe*)
S[x_, t_] := Sum[ Exp[- t  n^2] Integrate[x Sin[s n^2], {s, 0, \[Pi]}]  Sin[x n^2], {n, 5}]
(*controllability map*)
G[x_, t_] := indicator[x] S[x, T - t]
(*Grammian operator Q*)
Q[x_, t_] := (indicator[x])^2  Integrate[(S[x, T - s])^2, {s, T - l, T}]
v[x_, t_] := InverseFunction[a + Q][x, t];
N[v[w1 - S[1, T], T] ]

It's not working for me because of the expression of "h=a + Q" which is complicated

Best regards,

6 Replies
Posted 18 days ago

You can try something like this as long as h has a single value in the inverse domain.

Using Sin as an example

data = Table[{N@Sin[x], x}, {x, 0, Pi/2, Pi/200}];
invF = Interpolation[data];

invF[1/Sqrt[2]] / Degree
(* 45. *)

Sin[45 Degree]
(* 1/Sqrt[2] *)
Posted 17 days ago

Hi Rohit, I just edit my question, I specified the expression of the function to inverse! Do you have any idea why it's not working pleas?

To obtain proper help, show the h function in code or attached a notebook.

Posted 17 days ago

ok, I just edit my question.

Posted 17 days ago

This seems to be the same question as this.

Posted 17 days ago

Indeed yes, I have just checked it is my partner in this work who asked the question, I will send him a message so that he deletes this message not to repeat the same question.

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