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How to make it isolate the Beta parameter?

Hi,

I'm trying to isolate the beta parameter in the inequality belowenter image description here and that Mathematica give me the specified conditions such that the inequality is holding. I'm beginning in Mathematica so I'm not sure this is feasible as my computer is just stopping on Running for unlimited time (I've stopped after 1h30 minutes). I put the Mathematica file below also, Thanks in advance!

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POSTED BY: Xavier Koch
6 Replies
Posted 5 years ago

We will look at the issue from another perspective. Assume there is the one set of life data that is fitted using a Weibull distribution. This data set has a shape parameter β. If we separate the data into two groups and fit each group with a separate Weibull distribution, we get β1 and β2 as the shape parameters of the two groups. If we suppose that β1 < β2, will β1 < β < β2 always be true, or is there some other relationship between these beta values?

POSTED BY: Yasmin Hussain

Welcome to Wolfram Community! Please make sure you know the rules: https://wolfr.am/READ-1ST Please next time link your post to the duplicated one from MSE site.

POSTED BY: EDITORIAL BOARD
Posted 5 years ago

Crossposted here.

POSTED BY: Rohit Namjoshi
Posted 5 years ago
POSTED BY: Bill Nelson

Thanks a lot I will try that ! You just put a power 3 instead of power 2 on the right side of the inequality but correcting this it worked !

POSTED BY: Xavier Koch
Posted 5 years ago

Thank you for catching that. I apologize for my mistake.

With the correct equation it doesn't do as well isolating β. Not using Simplify and manually extracting the desired relation for β is perhaps better.

POSTED BY: Bill Nelson
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