# Wrong Differential Equations solutions?

Posted 10 years ago
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 Hello everyone.I tried to verify my solutions of Differential Equations today and I keep getting wrong results, at least I believe so. there is obviously a solution of c=1and here it should be "y(t)=c1+cos(2t)/4" instead.Interesting enough, if you change 2 to 3 you will get a good result.Of course here it doesn't calculate a particular solution either (eg. for given y=2 when t=(pi)/2).
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Posted 10 years ago
 Correct. I feel stupid asking after all, should've checked that. Doing maths at 3:30 in the morning isn't the best idea for me apparently.Thanks again.
Posted 10 years ago
 That is equivalent by trig identities.  The constant c_1 is different, though.
Posted 10 years ago
 Right, it works. Thank you sir.What about the second one?
Posted 10 years ago
 y=5 is interpreted as a constant function by Alpha.  Try "3dy/dx+x=6 where y(3)=5.5".
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