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Series limit with free parameter

Posted 3 years ago

Hello!

I am totally new to this. So, I am trying to input how to get the limit of a series with a parameter, ie like

$ a_n = \sqrt{(kn+2)} + \sqrt{(n)} , ~~k \in (0,+\infty )$

POSTED BY: Al Kas
4 Replies
RSolveValue[a[n] == Sqrt[k n + 2] + Sqrt[n], a[Infinity], n, Assumptions -> k > 0]

Or:

DiscreteLimit[Sqrt[k n + 2] + Sqrt[n], n -> \[Infinity], Assumptions -> k > 0]
POSTED BY: Mariusz Iwaniuk
Posted 3 years ago

That is great! Is there also a way to see the step-by-step solution ? Trying "show steps" does not seem to work nor appears anywhere.

POSTED BY: Al Kas

Probably not.

POSTED BY: Mariusz Iwaniuk

Hi,
Step-by-step solutions are available when you solve the problem using Wolfram Alpha. Avaibility of Wolfram Alpha Step-by-step solutions depends on what kind of license you have. For more info see

Examples for Step-by-Step Solutions or contact Wolfram Alpha team by

http://www.wolframalpha.com/contact.html
email: info@wolframalpha.com

POSTED BY: Ahmed Elbanna
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