Is it possible to generate Lah numbers in much the same way as generating Stirling numbers?
For example:
SM2 = Table[StirlingS2[i,j], {i,0,11},{j,0,11}]
What is the equivalent for Lah numbers?
Thanks Jim.
The brute force way might be simplest:
lah = Table[Binomial[n - 1, k - 1] n!/k!, {n, 0, 11}, {k, 0, 11}])
