Can Mathematica simplify an expression like Cos[2 Integers [Pi]] ?
Thanks, Rohit Namjoshi. The "Integers" in my post was the result of using "/. n->Integers" after the Simplify. It placed the double Z in the expression but didn't simpify. I'm still trying to learn the Mathematica order of operations.
Hi Jay,
You should read this for an overview of evaluation, and this for operator precedence.
What is Integers? Do you mean
Integers
Simplify[Cos[2 n π], n ∈ Integers] (* 1 *)