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Having trouble graphing a 3d graph with only x and y variables

Patrick Spriggs

Posted 9 years ago

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I am trying to do a project for school, and have to get a 3d graph using wolfram alpha. The problem is, that the equation is x^2 + 4y^2 = 4. This is only giving me a 2d graph, when I need the 3d graph, even though i try to make it do a 3d graph. Any help would be appreciated. Thank you!

POSTED BY: Patrick Spriggs

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Posted 9 years ago

An all too typical interaction with WolframAlpha, fumbling around trying to give it key words that I'm hoping might lead to some related result... It interrupts with a little popup wanting to know if I just cannot wait to find out what the wingspan of a mosquito is. With one well placed swat I exterminate that little interruption and continue my wandering Finally I happen to stumble onto something that looks like it works http://www.wolframalpha.com/input/?i=parametricplot3d%5B%7B2+Cos%5Bt%5D%2C+Sin%5Bt%5D%2C+z%7D%5D Knowing lots of Mathematica syntax and functions may help you stumble onto results, but I suspect that was exactly the opposite of the designers intentions. Or perhaps we were really just supposed to interested in Culicidae dimensions. Your experience may vary

POSTED BY: Bill Simpson

Posted 9 years ago

Mathematica understands this, so perhaps Alpha does as well. Note that this is a cylindrcal surface of infinite extent in z, so we need to truncate it somwhere, or the plot won't fit in the observable universe. ;-) ContourPlot3D[x^2 + 4 y^2 == 4, {x, -3, 3}, {y, -3, 3}, {z, -5, 5}]

POSTED BY: David Keith

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