How to put a variable angle?

Posted 11 months ago
1485 Views
|
4 Replies
|
2 Total Likes
|
 I can't figure out how to find this x? What am I doing wrong?
4 Replies
Sort By:
Posted 11 months ago
 There are many problems with the codev = 82*f[x_] should be v = 82*f[x], similarly for u.Take a look at eq02 0 == {{82 Cos[x] (t1 -> (280 Sec[x])/41) - 4.9 (t1 -> (280 Sec[x])/41)^2}} t1 need to be replaced with the solution for t t = t1 /. t[[1]] eq02 = 0 == u*t - (1/2)*g*(t^2) Solve[eq02, x] // N (* {{x -> -2.26376}, {x -> -0.877833}, {x -> 0.877833}, {x -> 2.26376}} *) 
Posted 11 months ago
 Thank you very much.
Posted 11 months ago
 There are syntax problems with your code. This gives an answer: f[x_] = Cos[x]; y[x_] = Cos[x]; v = 82*f[x]; u = 82*y[x]; hd = 560; g = 9.8; eq01 = hd == v*t1; t = t1 /. First@Solve[eq01, t1]; eq02 = 0 == u*t - (1/2)*g*(t^2); Angleanswer = Solve[eq02, x] 
Posted 11 months ago
 Thank you very much.
Community posts can be styled and formatted using the Markdown syntax.