Message Boards Message Boards

0
|
2563 Views
|
1 Reply
|
2 Total Likes
View groups...
Share
Share this post:

How do I plot this?

Posted 10 years ago
It has been a few days I've started using Mathematica. I learnt the basics using the Virtual Book. I'm now having a problem and am totally lost. There's a function


I need to plot J7 vs Lambda at Eta = 10^14 Hz taking the real part of J7. Can anyone please help me with this?
Thank you.
POSTED BY: Rohit Neoapne
I assume that the eta after the exponential in the first term is not in the exponential but is simply multiplying it.  If you are intersted in only the real part of your J7 expression then that's simply the first term as you've written it for real values of eta. 

So this is that integral:
In[20]:= (2/\[Pi])^(1/2)
  Integrate[\[Eta] x^7 Exp[-x^2/2]/(\[Eta]^2 + x^10), {x,
   0, \[Infinity]}, Assumptions -> {\[Eta] > 0}]


Out[20]= (\[Eta]^(3/5)
  MeijerG[{{1/5}, {}}, {{0, 1/5, 1/5, 2/5, 3/5, 4/5}, {}}, \[Eta]^2/
  100000])/(4 Sqrt[10] \[Pi]^(5/2))

The result in closeed form. Now all you need to do is substitute for eta and plot the result. However you do not say what the value of omega is.  The expression evaluated for your specified (omega dependent) value for lambda
 In[26]:= (\[Eta]^(3/5)
    MeijerG[{{1/5}, {}}, {{0, 1/5, 1/5, 2/5, 3/5, 4/5}, {}}, \[Eta]^2/
    100000])/(
  4 Sqrt[10] \[Pi]^(5/2)) /. {\[Eta] -> 0.28 10^5 \[Omega] \[Lambda]}
 
 
 Out[26]= 2.10552 (\[Lambda] \[Omega])^(3/5)
   MeijerG[{{1/5}, {}}, {{0, 1/5, 1/5, 2/5, 3/5, 4/5}, {}},
   7840. \[Lambda]^2 \[Omega]^2]
POSTED BY: David Reiss
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
Attachments
Remove
or Discard

Group Abstract Group Abstract