Hi, can anyone explain why "truth table ((a and (b and c)) equivalent ((a and b) and c)) " doesn't work on Wolfram|Alpha?
We are currently fixing this issue
This
(a && (b && c))==((a && b) && c)
returns
True (for any a,b,c)
Thanks for your help. This is quite weird. "truth table (a implies b) equivalent (not b implies not a)" works but "truth table ((a and (b and c)) equivalent ((a and b) and c)) " doesn't work,
