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Self dual tensors in Mathematica 9

Ofri Telem

Ofri Telem, Technion

Posted 12 years ago

Hi everybody, Is there any convenient way to define self dual tensors in mathematica? The best I could come up with is defining an antisymmetric tensor and summing it with its Hodge dual. But then Mathematica doesn't know that the tensor is self dual and thinks it has more degrees of freedom than it actually has, for example: sa4 = SymmetrizedArray[pos_ :> Subscript[a, pos], {8, 8, 8, 8}, Antisymmetric[All]]; (This should be 1 + 70, the number of D.O.F 's of a rank 4 antysymmetric tensor in 8 dimensions:) Length[SymmetrizedArrayRules[sa4]] 71 sa4star = HodgeDual[sa4]; sa4sum = sa4 + sa4star; sa4sum == HodgeDual[sa4sum] True (This should be 1 + 35, the number of D.O.F 's of a ~self-dual~ rank 4 antysymmetric tensor in 8 dimensions:) Length[SymmetrizedArrayRules[sa4sum]] 71 Is there a smarter way to define it? Thanks a lot, Ofri

Hi everybody,

Is there any convenient way to define self dual tensors in mathematica?

The best I could come up with is defining an antisymmetric tensor and summing it with its Hodge dual. But then Mathematica doesn't know that the tensor is self dual and thinks it has more degrees of freedom than it actually has, for example:

sa4 = SymmetrizedArray[pos_ :> Subscript[a, pos], {8, 8, 8, 8}, Antisymmetric[All]];

(*This should be 1 + 70, the number of D.O.F 's of a rank 4 antysymmetric tensor in 8 dimensions:*)
Length[SymmetrizedArrayRules[sa4]] 
71

sa4star = HodgeDual[sa4];
sa4sum = sa4 + sa4star;
sa4sum == HodgeDual[sa4sum]
True

(*This should be 1 + 35, the number of D.O.F 's of a ~self-dual~ rank 4 antysymmetric tensor in 8 dimensions:*)
Length[SymmetrizedArrayRules[sa4sum]]
71

Is there a smarter way to define it?

Thanks a lot, Ofri

POSTED BY: Ofri Telem

4 Replies

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Udo Krause

Udo Krause, NOrganization

Posted 12 years ago

not at all a beauty In[101]:= Clear[selfDT] selfDT[rk_Integer?Positive] := Block[{rg = Range[2 rk]}, SymmetrizedArray[ pos_ :> If[Signature[Join[pos, Complement[rg, pos]]] > 0, 1,(* else *) If[First[pos] == 1, 1, -1]] (a @@ If[First[pos] == 1, pos, Complement[rg, pos]]), 2 Table[rk, {rk}], Antisymmetric[All] ] ] /; EvenQ[rk] In[105]:= (# == HodgeDual[#]) & /@ Table[selfDT[o], {o, 2, 8, 2}] Out[105]= {True, True, True, True}

not at all a beauty

In[101]:= Clear[selfDT]
selfDT[rk_Integer?Positive] := 
 Block[{rg = Range[2 rk]}, 
   SymmetrizedArray[
     pos_ :> If[Signature[Join[pos, Complement[rg, pos]]] > 0, 1,(* else *) If[First[pos] == 1, 1, -1]] 
       (a @@ If[First[pos] == 1, pos, Complement[rg, pos]]), 2 Table[rk, {rk}], Antisymmetric[All]
   ]
 ] /; EvenQ[rk]

In[105]:= (# == HodgeDual[#]) & /@ Table[selfDT[o], {o, 2, 8, 2}]
Out[105]= {True, True, True, True}

POSTED BY: Udo Krause

Udo Krause

Udo Krause, NOrganization

Posted 12 years ago

To get rid of the reverse engineering one figures out what the HodgeDual[] is in tensor operations within an euclidean metric In[33]:= (* (i) Hodge Dual {a,b,c} ) Normal[LeviCivitaTensor[3] . {a, b, c}] Out[33]= {{0, c, -b}, {-c, 0, a}, {b, -a, 0}} replacing the Dot[] by canonical* operations it reads In[34]:= (* (ii) Hodge Dual {a,b,c} ) (1/1!) Normal[TensorContract[TensorProduct[LeviCivitaTensor[3], {a, b, c}], {3, 4}]] Out[34]= {{0, c, -b}, {-c, 0, a}, {b, -a, 0}} which makes it easy to apply it twice in order to create the identity In[35]:= ( HodgeDual HodgeDual {a,b,c} ) (1/2!) Normal[ ( HodgeDual ) TensorContract[TensorProduct[LeviCivitaTensor[3],( HodgeDual *) (1/1!) TensorContract[TensorProduct[LeviCivitaTensor[3], {a, b, c}], {3, 4}]], {{2, 4}, {3, 5}}]] Out[35]= {a, b, c} by the way this is in the references of the LeviCivitaTensor LeviCivitaTensor, Examples -> Applications

To get rid of the reverse engineering one figures out what the HodgeDual[] is in tensor operations within an euclidean metric

 In[33]:= (* (i) Hodge Dual {a,b,c} *)
Normal[LeviCivitaTensor[3] . {a, b, c}]
Out[33]= {{0, c, -b}, {-c, 0, a}, {b, -a, 0}}

replacing the Dot[] by canonical operations it reads

In[34]:= (* (ii) Hodge Dual {a,b,c} *)
(1/1!) Normal[TensorContract[TensorProduct[LeviCivitaTensor[3], {a, b, c}], {3, 4}]]
Out[34]= {{0, c, -b}, {-c, 0, a}, {b, -a, 0}}

which makes it easy to apply it twice in order to create the identity

In[35]:= (* HodgeDual HodgeDual {a,b,c} *)
(1/2!) Normal[ (* HodgeDual *)
  TensorContract[TensorProduct[LeviCivitaTensor[3],(* HodgeDual *) 
      (1/1!) TensorContract[TensorProduct[LeviCivitaTensor[3], {a, b, c}], {3, 4}]], {{2, 4}, {3, 5}}]]
Out[35]= {a, b, c}

by the way this is in the references of the LeviCivitaTensor LeviCivitaTensor, Examples -> Applications

POSTED BY: Udo Krause

Udo Krause

Udo Krause, NOrganization

Posted 12 years ago

Reverse engineering would impose something like that In[1]:= Clear[sa4sd, selfD, selfF] selfD[p_] := If[First[p] == 1, p, Complement[Range[8], p]] selfF[p_] := If[First[p] == 1, 1, 2] sa4sd = SymmetrizedArray[pos_ :> ((-1)^(Plus @@ pos))^selfF[pos] (a @@ selfD[pos]), {8, 8, 8, 8}, Antisymmetric[All]]; In[5]:= sa4sd == HodgeDual[sa4sd] Out[5]= True using the build-in Antisymmetric[All] pre-evaluation of pos. Still it holds In[7]:= TensorSymmetry[sa4sd] Out[7]= Antisymmetric[{1, 2, 3, 4}] With Mathematica 10 one possibly could use the Symmetry Specifications under TensorSymmetries directly.

Reverse engineering would impose something like that

In[1]:= Clear[sa4sd, selfD, selfF]
selfD[p_] := If[First[p] == 1, p, Complement[Range[8], p]]
selfF[p_] := If[First[p] == 1, 1, 2]
sa4sd = SymmetrizedArray[pos_ :> ((-1)^(Plus @@ pos))^selfF[pos] (a @@ selfD[pos]), {8, 8, 8, 8}, Antisymmetric[All]];

In[5]:= sa4sd == HodgeDual[sa4sd]
Out[5]= True

using the build-in Antisymmetric[All] pre-evaluation of pos. Still it holds

In[7]:= TensorSymmetry[sa4sd]
Out[7]= Antisymmetric[{1, 2, 3, 4}]

With Mathematica 10 one possibly could use the Symmetry Specifications under TensorSymmetries directly.

POSTED BY: Udo Krause

Udo Krause

Udo Krause, NOrganization

Posted 12 years ago

POSTED BY: Udo Krause

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