Given:
Pi*100 and 249/199
Step 1:
(249/199)^ 314.15926535897932384626433832795028841971693993751058209749445923… = 3.8214913787654748905284854586615014538508009040814238937966281958538026475649232937470897260918340989628066663464794030065... × 10^30
Step 2:
We will only take the number in front of the comma, which is 3821491378765474890528485458661 and put it to the power of 1/(100pi)) and then subtract it from 249/199.
(249/199)-3821491378765474890528485458661^(1/(100pi)) = 5.2263017941092574945015678282238729982530115527357040074410×10^(-34) = 0.00000000000000000000000000000000052263017941092574945015678282238729982530115527357040074410…
Step 3:
We can identify
0.00000000000000000000000000000000052263017941092574945015678282238729982530115527357040074410 as a huge fraction. 7584657648808 / 14512475451296987097254449394650542368989272025 = 0.00000000000000000000000000000000052263017941092574945015678282238729982530115527357040074410…
So when we subtract it from 249/199, we’ll have another huge fraction.
(249/199)- 7584657648808/ 14512475451296987097254449394650542368989272025 = 3613606387372949787216357899267983540531456621433/2887982614808100432353635429535457931428865132975
Step 4:
((249/199)-3821491378765474890528485458661^(1/(100pi)))+(3613606387372949787216357899267983540531456621433/2887982614808100432353635429535457931428865132975) = 249/199
Solution:
Pi might could simply be tricked by this straight-handed calculation method through computing around the remainder left from the number
3821491378765474890528485458661.50145385080090408142389379662… behind the comma and fill in the gap in the number system by the high resolution pattern of a infinite decimal remainder composure to puzzle fit Pi as a whole by putting all pieces together through taking
7584657648808/ 14512475451296987097254449394650542368989272025 and 3613606387372949787216357899267983540531456621433/2887982614808100432353635429535457931428865132975 as supposed sublimation for the integrated partial outtake and reinstigation to matching compliance.
Therefore,
X = (log(3613606387372949787216357899267983540531456621433/2887982614808100432353635429535457931428865132975)/ log(3821491378765474890528485458661))*100 = 1/pi
All the fractions are accurately fitting perfect as resolute components while being included parts.
Please notice that WolframAlpha here gives two different solution, one with remainder and one without one.
Because I checked the solutions on the composition of numbers, I am absolutely sure why it should be most precisely the best approximation for 1/Pi.
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