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Calculating the series development of 1/(1-2^(1-s))

Posted 2 years ago

Can Wolfram Alpha Pro calculate the series development of 1/(1-2^(1-s)) ?
What is the expression of series development 1/(1-2^(1-s)) ?
Does it use Bernouilli numbers and, in this case, what is the sum of Bernouilli numbers involved in the series expression?

POSTED BY: Chris Bianchi
4 Replies

With Mathematica:

enter image description here

From help pages: This message is generated when a sum specified in Sum is divergent.

With Regularization infinite series we have:

 Sum[1/(1 - 2^(1 - j)), {j, 2, m}][[1]]
 (*-(QPolyGamma[0, 1, 2]/Log[2])*)
 % // N
 (* 1.1067 *)

Regards M.I.

POSTED BY: Mariusz Iwaniuk

Mariusz, great answer (+1)!

This reminds me of "Ramanujan summation" - is it this you have in mind with your approach? Because "regular" Regularization options for Sum (e.g. "Euler", "Borel", etc.) do not give a closed solution here.

On the other hand by just omitting diverging terms one could argue like so:

summ = Sum[1/(1 - 2^(-s + 1)), {s, 2, \[FormalM]}];
(* series expansion about m=2, because 2 is the lowest index: *)
Series[summ, {\[FormalM], 2, 0}] // Normal // FullSimplify
(*  Out:   2  *)

Where am I wrong? Am I wrong? Regards -- Henrik

POSTED BY: Henrik Schachner

See here.

Regards M.I

POSTED BY: Mariusz Iwaniuk

Very interesting - many thanks for this link! Regards - H.S.

POSTED BY: Henrik Schachner
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