Let $b$ and $c$ be complex constants such that $z^2+b?z+c=0$ has two different real roots. Show that $b$ and $c$ are real.
How can they be real if they are complex constants?
1+0 I = 1
real is a special case of complex
Can you give me an example?
A real number is a complex number with an imaginary part equal to zero.
Let a complex number z = x + iy, with x,y real. The imaginary part of z is y, and z is real when y=0.
