Hi there,
Need help on solving for x5 in the following system:
x2 == 3 (5-x5) && x3 == 2 (3-x5) && x2>=0 && x3 >=0 && x5 >=0
I expect to have something like x5 <= 3, but Reduce gives the following solution:
(x2==6 && x3==0 && x5 ==3) || ....
Any suggestions on how to let MMA give x5 <= 3 as the solution?
Many thanks!
Xiangyang
