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Calculating residue at infinity

Bi Shengfan
Posted 6 months ago

When I was computing the residue at infinity, I encountered a slight issue. The second method of computation is correct, resulting in -3/2. Why does directly using the first formula to calculate the residue at infinity not yield the correct function value?
POSTED BY: Bi Shengfan
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The change of variables w=1/z will give dw=-1/z^2 dz. Maybe that sign is what you were missing?
POSTED BY: Daniel Lichtblau

The results seem correct to me, according to the definition of residue at infinity found on wikipedia
POSTED BY: Gianluca Gorni
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