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Is there a function that converts DateObjects to decimal years?

Posted 9 months ago

I have been seeing climate data sets that use decimal years. This is very convenient for some things. Is there a Mathematica function that converts DateObjects to decimal years?

POSTED BY: Kirk Hackett
5 Replies

Something like this?

1900. + AbsoluteTime[Today]/
  QuantityMagnitude[Quantity[1, "Years"], "Seconds"]
POSTED BY: Gianluca Gorni
Posted 9 months ago

Thanks! I’ll check it out.

POSTED BY: Kirk Hackett
Posted 9 months ago

Notice that

1900. + AbsoluteTime[{2024,12,31}]/QuantityMagnitude[Quantity[1,"Years"],"Seconds"]
(* 2025.03 *)

This seems better:

DateValue[{2024,12,31},"Year"] + DateValue[{2024,12,31},"YearFraction"]
(* 2024.95 *)
POSTED BY: Gustavo Delfino
Posted 9 months ago

By "decimal years" do you mean something like today (April 5) is 0.26 years from the beginning of the year?

DateDifference[DateObject[{2024, 1}], DateObject[{2024, 4, 5}], "Year"]
(* Quantity[0.25956284153005466, "Years"] *)
POSTED BY: Eric Rimbey
Posted 9 months ago

Thanks, Eric! I appreciate the help.

POSTED BY: Kirk Hackett
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