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PlotMarkers option messes up font sizes. How to get v9's default markers?

Posted 12 years ago
POSTED BY: James Stein
3 Replies

You have discovered an error which has already been fixed for a future version. GridLines->{Automatic, None} will remove the horizontal grid lines.

Module[{dates, vals, data, j, f, i, o}, 
 dates = Table[{2012, k, 1}, {k, 12}];
 vals = {1, 2, 3, 4, 5, 6, 6, 5, 4, 3, 2, 1};
 data = Transpose[{dates, vals}];
 j = Joined -> False;
 f = Filling -> Axis;
 i = ImageSize -> {150, 93};
 o = Sequence[data, j, f, i];
 DateListPlot[o, GridLines -> {Automatic, None}, 
  PlotTheme -> "Classic"]]
POSTED BY: Tim Shedelbower
Posted 12 years ago
POSTED BY: James Stein

James,

The point sizes in v10 adjust with the number of points. As the point quantity increases the point size decreases. The font size for "B" is 10 which is the default font size, so "A" and "B" are identical in size. v9 produces the same result except the font family is Times. Below are a few solutions you can try:

Module[{d3}, 
 d3 = {{1, 2, 3, 5, 8}, {2, 3, 6, 9, 10}, {4, 5, 7, 10, 12}};
 ListPlot[d3, 
  PlotMarkers -> {{"•", 20}, {"•", 15}, {"•", 10}}]]

Module[{d3}, 
 d3 = {{1, 2, 3, 5, 8}, {2, 3, 6, 9, 10}, {4, 5, 7, 10, 12}};
 ListPlot[d3, 
  PlotMarkers -> {Style["A", 10], Style["B", 8], Style["C", 6]}]]

Module[{d3}, 
 d3 = {{1, 2, 3, 5, 8}, {2, 3, 6, 9, 10}, {4, 5, 7, 10, 12}};
 ListPlot[d3, PlotTheme -> "PlotMarkers"]]

Module[{d3}, 
 d3 = {{1, 2, 3, 5, 8}, {2, 3, 6, 9, 10}, {4, 5, 7, 10, 12}};
 ListPlot[d3, PlotTheme -> "Classic"]]

The last example using PlotTheme->"Classic" will display v9 default markers.

Tim

POSTED BY: Tim Shedelbower
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