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calling variable that holds a previous output.

I have a equation system with two variables. And the Mathematica gives a solution.

How can I call this solution a line down to do another calc.

This question is for automatization process I'm doing.

Solve[x + y == 2 && x - y == 1, {x, y}] {{x -> 3/2, y -> 1/2}}
POSTED BY: Harvey Vargas
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Douglas Kubler
Douglas Kubler
Posted 11 years ago

You're missing a semicolon

sol = Solve[x + y == 2 && x - y == 1, {x, y}]; x = x /. Flatten[sol]; y = y /. Flatten[sol]

Undo the symbol damage with Clear["x"];Clear["y"]; Re-execute and your answers will be OK.
POSTED BY: Douglas Kubler

This is how I save it

sol = Solve[x + y == 2 && x - y == 1, {x, y}]; x = x /. Flatten[sol] y = y /. Flatten[sol]

It says is an error
POSTED BY: Harvey Vargas
Jim Baldwin
Jim Baldwin, Retired
Posted 11 years ago 
(* Original equation *)
sol = Solve[x + y == 2 && x - y == 1, {x, y}]

(* Use solution for another function of x and y *)
x + 7 y /. Flatten[sol]
POSTED BY: Jim Baldwin
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