Group Abstract Group Abstract

Message Boards Message Boards

0
|
1.3K Views
|
2 Replies
|
0 Total Likes
View groups...
Share
Share this post:

What is this MeijerG Function

Posted 1 year ago

After following integral, I got a MeijerG result,

Integrate[(1/(2 r (1 + r^2))*Sin[r])^2*r, {r, 0, \[Infinity]}]

Out=1/16 Sqrt[\[Pi]] MeijerG[{{1, 1}, {}}, {{1, 2}, {0, 1/2}}, 1]

I don't know what is MeijerG[{{1, 1}, {}}, {{1, 2}, {0, 1/2}}, z],

I tried Activate command, it gives same result.

So I checked online and found MeijerG function in Mathematica should be:

MeijerG[{{a1,...,an},{an+1,...,ap}},{{b1,...,bm},{bm+1,...,bq}},z,]

So I believe bm+1 should be greater than bm and so does bq is greater than bm too.
However, the MeijerG function I got is MeijerG[{{1, 1}, {}}, {{1, 2}, {0, 1/2}}, 1],
bm=2 and bm+1=0 and bq=1/2, which means both bm+1 and bq is less than bm.

I am confused. Anyone can help me? I don't think this is a mistake of Mathematica.

POSTED BY: Qiang Lu
2 Replies
POSTED BY: Michael Rogers

Thanks, Michael, that answered my question.

POSTED BY: Qiang Lu
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
Attachments
Remove
or Discard