Message Boards Message Boards

0
|
2961 Views
|
3 Replies
|
0 Total Likes
View groups...
Share
Share this post:
GROUPS:

What did I do wrong, not getting two PolarPlots.

Anonymous User
Anonymous User
Posted 10 years ago

PolarPlot[{2 Sin[3 x], 1 + Cos^2[3 x]^2}, {x, 0, 2 [Pi]}]

POSTED BY: Anonymous User
3 Replies

It works when you input: PolarPlot[{2 Sin[3 x], 1 + (Cos[3 x])^2}, {x, 0, 2 Pi}]

POSTED BY: S M Blinder
Anonymous User
Anonymous User
Posted 10 years ago

the two equations i wanted were r= 2Sin(3x) and r= 1+Cos^2(3x)

POSTED BY: Anonymous User

You probably need the following syntax. I assumed you wanted cos^2((3x)^2))

PolarPlot[{2 Sin[3 x], 1 + Cos[(3 x)^2]^2(*cos^2 must be (Cos[])^2*)}, {x, 0, 2 Pi(*without the [] around Pi*)}]
POSTED BY: Isaac Abraham
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
Attachments
Remove
or Discard

Group Abstract Group Abstract