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How to obtain such a result when solving the system of equations?

Posted 4 days ago
Clear[f]
f[x_] = 2 E^(2 x) - a (x - 1)
Reduce[{f[x1] == 0, f[x2] == 0}, a, Reals]

The desired final result is as shown below:

a == (E^(2 x2) - E^(2 x1))/(x2 - x1)

enter image description here

POSTED BY: Bill Blair
3 Replies

Your desired final result does not seem to follow from the premises:

Clear[f, x, x1, x2, a];
f[x_] = 2 E^(2 x) - a (x - 1);
twoConds = f[x1] == 0 && f[x2] == 0;
thirdCond = a == (E^(2 x2) - E^(2 x1))/(x2 - x1);
counterExample = {x1 -> 2, x2 -> 1 - 1/2 ProductLog[-(2/E^2)], 
   a -> 2 E^4};
{twoConds, thirdCond} /. counterExample // Simplify
POSTED BY: Gianluca Gorni

POSTED BY: Mariusz Iwaniuk
Posted 4 days ago

Thank you very much! Changing the equation form a bit gave the desired solution.

POSTED BY: Bill Blair
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