Dear Community:
How does one derive the d(tau), which is r^2*[Sin(theta)]d(r)d(theta)d(phi) from d(x)d(y)d(z)?
Thank you,Patrick Merrill
Dear Gianluca,
Perfect!
Thank you!!
Patrick Merrill
Faster:
CoordinateChartData["Spherical", "VolumeFactor", {r, \[Theta], \[CurlyPhi]}]
Here is a way:
D[FromSphericalCoordinates[{r, \[Theta], \[CurlyPhi]}], {{r, \[Theta], \[CurlyPhi]}}] // Det // Simplify
